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6y^2+15y-16=0
a = 6; b = 15; c = -16;
Δ = b2-4ac
Δ = 152-4·6·(-16)
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{609}}{2*6}=\frac{-15-\sqrt{609}}{12} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{609}}{2*6}=\frac{-15+\sqrt{609}}{12} $
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